Rhombus Formulas

8. Rhombus Formulas

A rhombus is a quadrilateral in which all four sides are equal.

In the rhombus diagram, each side is represented by a, while the two diagonals are represented by d₁ and d₂.

The important rhombus formulas given in the formula sheet are related to its diagonals, area, perimeter and diagonal relation.

What Is a Rhombus?

D C B A O a a a a d₁ d₂ 90°

d₁ and d₂ are the two diagonals, and a is the length of each side.

1. Diagonals of a Rhombus

The diagonals of a rhombus bisect each other at 90°.

Diagonals bisect each other at 90°

This means that the two diagonals intersect at right angles and each diagonal divides the other into two equal parts.

Important:

If the diagonals intersect at point O, then:

AO = OC
BO = OD

and the angle between the diagonals is:

90°

2. Area of a Rhombus

The area of a rhombus can be found using its two diagonals.

Area = ½ × d₁ × d₂

Where:

  • d₁ = First diagonal
  • d₂ = Second diagonal

Example 1: Find the Area

A rhombus has diagonals of length 12 cm and 8 cm. Find its area.

Area = ½ × d₁ × d₂

= ½ × 12 × 8

= 6 × 8

= 48 cm²

Answer: 48 cm²

Example 2: Find a Missing Diagonal

The area of a rhombus is 60 cm² and one diagonal is 10 cm. Find the other diagonal.

Using:

A = ½ × d₁ × d₂

Therefore:

d₂ = 2A ÷ d₁

d₂ = (2 × 60) ÷ 10

d₂ = 12 cm

Answer: 12 cm

3. Perimeter of a Rhombus

All four sides of a rhombus are equal. If each side has length a, then:

Perimeter = 4a

Example 1

Each side of a rhombus is 9 cm. Find its perimeter.

P = 4a

P = 4 × 9

P = 36 cm

Answer: 36 cm

Example 2: Find the Side

The perimeter of a rhombus is 52 cm. Find the length of each side.

a = P ÷ 4

a = 52 ÷ 4

a = 13 cm

Answer: 13 cm

4. Diagonal Relation of a Rhombus

The PDF gives an important relationship between the two diagonals and the side of a rhombus:

d₁² + d₂² = 4a²

Where:

  • d₁ = First diagonal
  • d₂ = Second diagonal
  • a = Side of the rhombus

Why Does This Relation Work?

Since the diagonals of a rhombus bisect each other at 90°, half of each diagonal and one side form a right-angled triangle.

Using the Pythagorean theorem:

a² = (d₁/2)² + (d₂/2)²

Multiplying by 4:

4a² = d₁² + d₂²

Example 1

The diagonals of a rhombus are 6 cm and 8 cm. Find its side.

d₁² + d₂² = 4a²

6² + 8² = 4a²

36 + 64 = 4a²

100 = 4a²

a² = 25

a = 5 cm

Answer: 5 cm

Example 2: Verify the Diagonal Relation

A rhombus has side 5 cm and diagonals 6 cm and 8 cm. Verify the formula.

Left side:

d₁² + d₂² = 6² + 8²

= 36 + 64

= 100

Right side:

4a² = 4 × 5²

= 4 × 25

= 100

Therefore:

100 = 100 ✓

Hence, the relation is verified.

5. Finding the Side Using the Diagonals

From:

d₁² + d₂² = 4a²

we can rearrange the formula to find the side:

a = ½√(d₁² + d₂²)

Example

The diagonals of a rhombus are 10 cm and 24 cm. Find the side.

a = ½√(d₁² + d₂²)

= ½√(10² + 24²)

= ½√(100 + 576)

= ½√676

= ½ × 26

a = 13 cm

Answer: 13 cm

6. Area and Perimeter of a Rhombus

Quantity Formula Unit
Area ½ × d₁ × d₂ Square units
Perimeter 4a Length units
Diagonal Relation d₁² + d₂² = 4a² Squared units
Remember:

Area uses the two diagonals.

Perimeter uses the side.

Diagonal relation connects the two diagonals with the side.

7. Combined Exam Example

A rhombus has diagonals of 12 cm and 16 cm. Find:

  1. Its area
  2. Its side
  3. Its perimeter

Step 1: Area

A = ½ × d₁ × d₂

= ½ × 12 × 16

A = 96 cm²

Step 2: Side

a = ½√(d₁² + d₂²)

= ½√(12² + 16²)

= ½√(144 + 256)

= ½√400

a = 10 cm

Step 3: Perimeter

P = 4a

= 4 × 10

P = 40 cm

Final Answers:

  • Area = 96 cm²
  • Side = 10 cm
  • Perimeter = 40 cm

8. Common Mistakes in Rhombus Questions

Mistake 1: Forgetting that all sides are equal

For a rhombus:

a = a = a = a

Therefore:

P = 4a

Mistake 2: Forgetting the ½ in the area formula

The correct formula is:

A = ½ × d₁ × d₂

Mistake 3: Forgetting that diagonals are perpendicular

The diagonals of a rhombus bisect each other at 90°.

Mistake 4: Using the parallelogram diagonal relation

For a rhombus, the source gives:

d₁² + d₂² = 4a²

Do not confuse it with the general parallelogram relation.

9. Rhombus Formula Chart

Concept Formula / Property
Diagonal Property Diagonals bisect each other at 90°
Area ½ × d₁ × d₂
Perimeter 4a
Diagonal Relation d₁² + d₂² = 4a²
Side from Diagonals ½√(d₁² + d₂²)

10. Practice Questions

Question 1: A rhombus has diagonals 14 cm and 10 cm. Find its area.

Question 2: Each side of a rhombus is 15 cm. Find its perimeter.

Question 3: The diagonals of a rhombus are 6 cm and 8 cm. Find its side.

Question 4: The area of a rhombus is 120 cm² and one diagonal is 12 cm. Find the other diagonal.

Question 5: The diagonals of a rhombus are 10 cm and 24 cm. Find its side and perimeter.

Question 6: A rhombus has side 13 cm and one diagonal 10 cm. Using the diagonal relation, find the other diagonal.

11. Rhombus Formula Quick Revision

Diagonals: Bisect each other at 90°
Area: ½ × d₁ × d₂
Perimeter: 4a
Diagonal Relation: d₁² + d₂² = 4a²
Side: ½√(d₁² + d₂²)

12. Mensuration Exam Tip

When a rhombus question gives the two diagonals, think of the area formula first:

A = ½ × d₁ × d₂

When the question asks for the side from the diagonals, use:

a = ½√(d₁² + d₂²)

When the question asks for the perimeter, use:

P = 4a
Next Part:

In Part 9 — Trapezium Formulas, we will cover perimeter, area, height, diagonals and the important diagonal relation of a trapezium, with diagrams, explanations, solved examples, practice questions and exam tips.