General Triangle Formulas

11. General Triangle Formulas

A general triangle is a triangle in which the three sides and three angles may be different.

Let the three sides of a triangle be a, b and c.

For general triangle problems, some of the most important formulas are:

  • Semiperimeter
  • Area using Heron's formula
  • Area using two sides and included angle
  • Area using base and height
  • Perimeter
  • Inradius

What Is a General Triangle?

b a c h C A B C A B

a, b, c = sides   |   h = height

1. Symbols Used in Triangle Formulas

Symbol Meaning
a First side
b Second side
c Third side
s Semiperimeter
h Height / altitude
A Area of triangle
r Inradius
C Included angle between sides a and b

2. Semiperimeter of a Triangle

The semiperimeter is half of the perimeter of the triangle.

s = (a + b + c) / 2

The symbol s represents the semiperimeter.

Example

The sides of a triangle are 5 cm, 6 cm and 7 cm. Find its semiperimeter.

s = (a + b + c) / 2

= (5 + 6 + 7) / 2

= 18 / 2

s = 9 cm

Answer: 9 cm

3. Heron's Formula

When all three sides of a triangle are known, its area can be found using Heron's formula.

A = √[s(s − a)(s − b)(s − c)]

Here:

  • A = Area
  • a, b, c = three sides
  • s = semiperimeter

Important: First calculate the semiperimeter before applying Heron's formula.

Example: Heron's Formula

Find the area of a triangle whose sides are 5 cm, 6 cm and 7 cm.

Step 1: Find Semiperimeter

s = (5 + 6 + 7) / 2

s = 9 cm

Step 2: Apply Heron's Formula

A = √[s(s − a)(s − b)(s − c)]

= √[9(9 − 5)(9 − 6)(9 − 7)]

= √(9 × 4 × 3 × 2)

= √216

A = 6√6 cm²

Approximately:

A ≈ 14.70 cm²

4. Area Using Two Sides and Included Angle

If two sides and the angle between those two sides are known, the area can be calculated using:

A = ½ab sin C

Here:

  • a = first side
  • b = second side
  • C = angle between sides a and b

Example

Two sides of a triangle are 8 cm and 10 cm. The included angle is 30°. Find the area.

A = ½ab sin C

= ½ × 8 × 10 × sin 30°

Since:

sin 30° = ½

Therefore:

A = ½ × 8 × 10 × ½

A = 20 cm²

Answer: 20 cm²

5. Important Sine Values for Triangle Questions

Angle sin θ
0° 0
30° 1/2
45° 1/√2
60° √3/2
90° 1

6. Area Using Base and Height

The basic area formula for any triangle is:

A = ½ × Base × Height

If the base is b and the corresponding height is h:

A = ½bh

Example

The base of a triangle is 14 cm and its corresponding height is 9 cm. Find the area.

A = ½bh

= ½ × 14 × 9

= 7 × 9

A = 63 cm²

Answer: 63 cm²

7. Finding Height from Area

From:

A = ½bh

the height can be calculated as:

h = 2A / b

Example

The area of a triangle is 96 cm² and its base is 16 cm. Find the height.

h = 2A / b

= (2 × 96) / 16

= 192 / 16

h = 12 cm

Answer: 12 cm

8. Perimeter of a General Triangle

The perimeter is the sum of all three sides.

P = a + b + c

Example

The sides of a triangle are 9 cm, 12 cm and 15 cm. Find its perimeter.

P = a + b + c

= 9 + 12 + 15

P = 36 cm

Answer: 36 cm

9. Inradius of a Triangle

The inradius is the radius of the circle that lies inside the triangle and touches all three sides.

For a triangle:

r = A / s

where:

  • r = inradius
  • A = area
  • s = semiperimeter

Example

The area of a triangle is 84 cm² and its semiperimeter is 14 cm. Find its inradius.

r = A / s

= 84 / 14

r = 6 cm

Answer: 6 cm

10. Inradius Using Heron's Formula

If the three sides are known, first find the semiperimeter and area. Then:

r = A / s

Since:

A = √[s(s − a)(s − b)(s − c)]

the inradius can also be expressed as:

r = √[(s − a)(s − b)(s − c) / s]

Example

Find the inradius of a triangle with sides 5 cm, 6 cm and 7 cm.

We already know:

s = 9 cm

and:

A = 6√6 cm²

Therefore:

r = A / s

= 6√6 / 9

r = 2√6 / 3 cm

Approximately:

r ≈ 1.63 cm

11. Important Relation Between Area, Inradius and Semiperimeter

A very important mensuration relation is:

A = rs

Therefore:

r = A / s

and:

s = A / r

12. Combined Exam Example

The sides of a triangle are 13 cm, 14 cm and 15 cm. Find:

  1. Perimeter
  2. Semiperimeter
  3. Area
  4. Inradius

Step 1: Perimeter

P = a + b + c

= 13 + 14 + 15

P = 42 cm

Step 2: Semiperimeter

s = P / 2

= 42 / 2

s = 21 cm

Step 3: Area Using Heron's Formula

A = √[s(s − a)(s − b)(s − c)]

= √[21(21 − 13)(21 − 14)(21 − 15)]

= √(21 × 8 × 7 × 6)

= √7056

A = 84 cm²

Step 4: Inradius

r = A / s

= 84 / 21

r = 4 cm

Final Answers:

  • Perimeter = 42 cm
  • Semiperimeter = 21 cm
  • Area = 84 cm²
  • Inradius = 4 cm

13. Which Triangle Area Formula Should You Use?

Given Information Use This Formula
Base and corresponding height A = ½bh
Three sides A = √[s(s−a)(s−b)(s−c)]
Two sides and included angle A = ½ab sin C
Area and semiperimeter r = A/s
Three sides s = (a+b+c)/2

14. Common Mistakes in General Triangle Questions

Mistake 1: Forgetting the ½

The basic area formula is:

A = ½bh

Mistake 2: Using the wrong angle

For:

A = ½ab sin C

C must be the angle between sides a and b.

Mistake 3: Using Heron's formula without finding s

Always calculate:

s = (a+b+c)/2

before applying Heron's formula.

Mistake 4: Confusing perimeter and semiperimeter

Perimeter = a+b+c
Semiperimeter = (a+b+c)/2

Mistake 5: Mixing units

Make sure all sides and heights are converted to the same unit before calculating the area.

15. General Triangle Formula Chart

Quantity Formula
Perimeter P = a+b+c
Semiperimeter s = (a+b+c)/2
Area — Base & Height A = ½bh
Area — Heron's Formula A = √[s(s−a)(s−b)(s−c)]
Area — Two Sides & Angle A = ½ab sin C
Inradius r = A/s
Area-Inradius Relation A = rs

16. Practice Questions

Question 1: Find the semiperimeter of a triangle whose sides are 8 cm, 10 cm and 12 cm.

Question 2: Find the perimeter of a triangle whose sides are 15 cm, 18 cm and 20 cm.

Question 3: Find the area of a triangle with base 16 cm and height 12 cm.

Question 4: Find the area of a triangle whose sides are 5 cm, 5 cm and 6 cm using Heron's formula.

Question 5: Two sides of a triangle are 12 cm and 10 cm and the included angle is 30°. Find the area.

Question 6: A triangle has area 120 cm² and semiperimeter 20 cm. Find its inradius.

Question 7: The area of a triangle is 150 cm² and its base is 15 cm. Find its height.

Question 8: The sides of a triangle are 13 cm, 14 cm and 15 cm. Find its area and inradius.

17. General Triangle Quick Revision

Perimeter: a + b + c
Semiperimeter: (a + b + c) / 2
Area: ½bh
Heron's Formula: √[s(s−a)(s−b)(s−c)]
Two Sides & Included Angle: ½ab sin C
Inradius: A / s
Area Relation: A = rs

18. Mensuration Exam Tip

When you see a triangle question, first identify what information is given.

  • Base + Height → use A = ½bh
  • Three sides → use Heron's formula
  • Two sides + included angle → use A = ½ab sin C
  • Area + semiperimeter → use r = A/s

This simple identification step can save considerable time in competitive examinations.

Formula Source:

The General Triangle formulas in this section are based on the provided mensuration formula sheet, which lists semiperimeter, Heron's formula, the two-side included-angle area formula, base-height area formula, perimeter and inradius.

Next Part:

Part 12 — Right-Angled Triangle Formulas will cover area, perimeter, Pythagoras theorem, altitude to the hypotenuse, important relationships and solved competitive-exam examples.

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